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Mathematics 12 Online
OpenStudy (anonymous):

help i don't know how to input this answer !!!! i will become your fan and give you a medal ! thank you bye

OpenStudy (anonymous):

OpenStudy (anonymous):

you can use the sine function

OpenStudy (anonymous):

sine function ?

hartnn (hartnn):

whats your answer ?

OpenStudy (anonymous):

hypotenuse =3

hartnn (hartnn):

thats not correct

OpenStudy (anonymous):

do i put x=3?

OpenStudy (anonymous):

oh

hartnn (hartnn):

have you learnt the apecial properties of a 30-60-90 triangle ?

hartnn (hartnn):

the *special

OpenStudy (anonymous):

no

hartnn (hartnn):

here'e one : side opposite to 60 degree angle is \(\Large \dfrac{\sqrt3}{2}\) times the hypotenuse

hartnn (hartnn):

so, you have \(\Large 3 = \dfrac{\sqrt3}{2}H\) can you find H from here ?

hartnn (hartnn):

H = hypotenuse

OpenStudy (anonymous):

is that the formula

hartnn (hartnn):

yes, its a special property, only applicable to 30-60-90 triangle

OpenStudy (anonymous):

OH ok i think i understand but the hypotenuse is missing so do you know that formula ?

hartnn (hartnn):

i gave you the formula for hypotenuse only....H there is hypotenuse...calculate that

OpenStudy (anonymous):

thank you for your help :)

hartnn (hartnn):

\(\Large 3 = \dfrac{\sqrt3}{2}H \\ H = \dfrac{3\times 2 }{\sqrt 3 } = ...\)

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