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OpenStudy (anonymous):
help i don't know how to input this answer !!!!
i will become your fan and give you a medal ! thank you bye
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OpenStudy (anonymous):
OpenStudy (anonymous):
you can use the sine function
OpenStudy (anonymous):
sine function ?
hartnn (hartnn):
whats your answer ?
OpenStudy (anonymous):
hypotenuse =3
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hartnn (hartnn):
thats not correct
OpenStudy (anonymous):
do i put x=3?
OpenStudy (anonymous):
oh
hartnn (hartnn):
have you learnt the apecial properties of a 30-60-90 triangle ?
hartnn (hartnn):
the *special
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OpenStudy (anonymous):
no
hartnn (hartnn):
here'e one :
side opposite to 60 degree angle is \(\Large \dfrac{\sqrt3}{2}\) times the hypotenuse
hartnn (hartnn):
so, you have
\(\Large 3 = \dfrac{\sqrt3}{2}H\)
can you find H from here ?
hartnn (hartnn):
H = hypotenuse
OpenStudy (anonymous):
is that the formula
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hartnn (hartnn):
yes, its a special property, only applicable to 30-60-90 triangle
OpenStudy (anonymous):
OH ok i think i understand but the hypotenuse is missing so do you know that formula ?
hartnn (hartnn):
i gave you the formula for hypotenuse only....H there is hypotenuse...calculate that
OpenStudy (anonymous):
thank you for your help :)
hartnn (hartnn):
\(\Large 3 = \dfrac{\sqrt3}{2}H \\ H = \dfrac{3\times 2 }{\sqrt 3 } = ...\)
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