Question

Simplify \(\frac{cos^{2}a}{1-tana} + \frac{sin^{2}a}{1-cota}\)

Answer 1

\[\large \frac{\cos^2a}{1-\tan a}+\frac{\sin^2a}{1-\cot a}=
\frac{\cos^2a}{1-\tan a}+\frac{\sin^2a}{1-\frac{1}{\tan a}}= \]
\[\large =\frac{\cos^2a}{1-\tan a}+\frac{(\tan a)(\sin^2a)}{\tan a-1}=
\frac{\cos^2a}{1-\tan a}-\frac{(\tan a)(\sin^2 a)}{1-\tan a} \]

Answer 2

but you should Simplify it

Answer 3

\[\large =\frac{\cos^2a-(\tan a)(\sin^2a)}{1-\tan a}=
\frac{\cos^2a-(\tan a)(1-\cos^2a)}{1-\tan a}= \]
\[\large =\frac{\cos^2a-\tan a+(\tan a)(\cos^2a)}{1-\tan a} \]

Answer 4

i know.that is what i was trying to do