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OpenStudy (anonymous):
How many committees of 5 people can be selected from 7 men and 7 women if the committee must have 3men and 2 women?
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OpenStudy (yttrium):
\[(7C3)(7C2)\]
OpenStudy (yttrium):
\[\(\frac{ 7! }{ 4!3! }) (\frac{ 7! }{ 5!2! })\]
OpenStudy (anonymous):
Wow thank you! How did you know what to do?
OpenStudy (yttrium):
It's basically combinatorics.
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