Question

In isosceles triangle ABC, ∠A = 80°. The bisectors of the base angles, ∠B and ∠C, intersect at point P.

∠BPC =



50°


100°


130°

Answer 1

Angle B and angle C measures 50 deg ( the base angles in isosceles triangle is equal)
Bisect or is drawn....which means the 50deg is divided into half That is 25deg
Therefore angle p measure 180-25-25=130deg

Answer 2

thank you