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Mathematics 20 Online
OpenStudy (anonymous):

how do i prove this trigonometric identity?

OpenStudy (anonymous):

OpenStudy (anonymous):

\(\large \frac{\sin 2\alpha}{\sin \alpha}-\frac{\cos 2\alpha}{\cos \alpha}\)

OpenStudy (anonymous):

\(\sin 2 \alpha=2\sin \alpha\cos\alpha\)

OpenStudy (anonymous):

still there ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and cos2 a = cos^2a - sin ^2 a

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