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Mathematics 9 Online
OpenStudy (anonymous):

How would I find the critical values of : sin x + cos x (0

OpenStudy (anonymous):

Take the derivative, then set it equal to 0

OpenStudy (anonymous):

cosx - sinx = 0

OpenStudy (anonymous):

cosx = sinx 1 = tanx x =? Can you solve it from here

OpenStudy (anonymous):

Sorry, just sat back down.

OpenStudy (anonymous):

Sorry, how did you get that derivative.

OpenStudy (anonymous):

\[4\sqrt[4]{x ^{3}}-2\sqrt{x}\]

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