Question

Find three consecutive positive even integers such that the product of the second and third is twenty more than ten times the first integer

Answer 1

Let n be the middle number. Then the numbers are:
{n - 2, n, n + 2}
Solve the following for n:
n (n + 2) = 20 + 10 (n - 2)
n = 8
{6, 8, 10}