Question

find center and radius with endpoints of diameter, (-7,52) and (15,26) thanks to all who help

Answer 1

\[\sqrt{(x1-x2)^{2 }+(y1-y2)^{2}} = distance\]

Answer 2

so you can use the distance formula to compute the magnitude of the line with points (-7,52) and \[d=\sqrt{(26-52)^{2}+(15--(7))^{2}}\](15,26)
then you can half the quantity and obtain the radius

Answer 3

okay but how do I find center for anyone viewing?

Answer 4

do I use midpoint formula?