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Mathematics 8 Online
OpenStudy (anonymous):

how to prove trigonometric identity?

OpenStudy (anonymous):

OpenStudy (anonymous):

\[\sin 3 \alpha=\sin \left( 2 \alpha+\alpha \right)=?\]

OpenStudy (anonymous):

4sin^3α

OpenStudy (anonymous):

\[\sin \left( \alpha+\beta \right)=\sin \alpha \cos \beta+\cos \alpha \sin \beta\]

OpenStudy (anonymous):

\[\sin \left( 2 \alpha+\alpha \right)=\sin 2 \alpha \cos \beta +\cos 2 \alpha \sin \beta \] \[=2 \sin \alpha \cos \alpha \cos \alpha +\left( 1- 2\sin ^2 \alpha \right)\sin \alpha \] \[=2 \sin \alpha \left( 1-\sin ^2 \alpha \right)+\sin \alpha - \sin ^3\alpha=?\]

OpenStudy (anonymous):

correction \[=2 \sin \alpha \left( 1-\sin ^2 \alpha \right)+\sin \alpha -2 \sin ^3 \alpha =?\]

OpenStudy (anonymous):

4sin^3α ?

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