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A box contains 20 cards numbered 1-20. You select a card. Without replacing the first card, you select a second card. Find each probability P(1, then 20) P(even, then 7)
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P(1) = 1/20 and P(20) = 1/19 therefore P(1 and 20) = P(1) * P(20|1) = 1/20 * 1/19 = .... part b is samething like part a
So the answer would be 1/380
yes, for the 1st one
Ok thank you, would you mind helping me set up the second one please
1-20, how many even numbers are there ?
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10
yup, so P(even) = 10/20 and P(7) = 1/19, right ?
YES
Then multiply them together ?
yup
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10/380
you got it!
Thanks for your help!!
yoyu're welcome
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