Question

Create a quadratic function with two real zeros.

Answer 1

x^2+3x+2=0
(x+2)(x+1)=0
x+2=0
x+1=0
x= -2 , -1
so roots of the equation are -2 & -1
lets check if they are zeros as well

putting -2 in eq
(-2)^2 + 3(-2)+2=0
4-6+2=0
-6+6=0
0=0
hence -2 is a zero

putting -1 in eq
(-1)^2 + 3(-1)+2=0
1-3+2=0
-3+3=0
0=0
hence -1 is a zero as well

Answer 2

I hope you get it :)