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Sixth Grade algebra help? Medal+fan for helpful answer Evaluate: \[x ^{2} -2xy-y ^{2}\] for x=-2 and y=3
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\[-2^{2}-2(-2)(3)-3^{2}\]
\[4+12-9\]
16-9= 7
How did you get that? I kept getting -1.
from where
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Im not sure I kept working -4 -2(-6)-9
wait....that wouldn't be -1..i dunno what I kept doing but I got it wrong on my homework.
Well thanks anyway :)
\[-2^{2}=4 and -2(-2)(3)=12and -3^{2}=9\]
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