Question

which would represent, cos theta(sec theta-cos theta), simplified as a single trig expression?

Answer 1

Hi
where are your options?

Answer 2

1)cos^2 2)csc^2 3)sin^2 4)Sec^2

Answer 3

\[\cos\theta(\sec \theta-\cos \theta) =\cos \theta \sec \theta-\cos^2 \theta\]is that right?

Answer 4

thats not the equation but thats what it would equal when distributed

Answer 5

do you know formula for the \(\sec \theta\) ?

Answer 6

1/cos theta

Answer 7

so\[\cos\theta(\sec \theta-\cos \theta) =\cos \theta \sec \theta-\cos^2 \theta\]\[=\cos \theta \frac{1}{\cos \theta}-\cos^2 \theta=1-\cos^2 \theta=\sin^2 \theta\]option 3 is your answer, is it clear for you?

Answer 8

yes, thanks for the quick reply

Answer 9

no problem :-)