The perimeter of the rectangle below is 128 units. Find the length of side VW . Write your answer without variables.
We know that the perimeter of a rectangle is \[\large Perimeter = 2L + 2W\] If the length = 3y + 1 and the width = 2y + 3 we have \[\large Perimeter = 2(3y + 1) + 2(2y + 3)\] That perimeter is 128 so we have \[\large 128 = 2(3y + 1) + 2(2y + 3)\] Now we need to solve that equation for 'y'
can you solve that for 'y' ?
i think i did something wrong
No you are completely correct! \[\large 128 = 10y + 8\]
Now subtract 8 from both sides...and then divide both sides by 10 to solve for 'y'
Thank You So Much !!
And that would have shown that y = 12... and to find the length of VW plug in 12 for 'y' \[\large 3y + 1 \rightarrow 3(12) + 1 = 37\]
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