Question

7-5 exponential logarithmic equatiions.
solve
5^2x=20

Answer 1

.... help

Answer 2

\[5^{2x}=20\]Take log of both sides\[\log{5^{2x}}=\log{20}\]\[2x\log{5}=\log{20}\]\[x=\frac{\log{20}}{2\log{5}}\]You can reduce further if you want to factor out down to just the logs of prime numbers.

Answer 3

But the doesn't the 2 stay with the X and at the and you dive it by 2.
if you reduce it, it would be
2x=1.8613.....
1.8613.../2
x=0.930..

Answer 4

it is the same thing

Answer 5

okay thank you so much