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3x^2-7x-4=0 A. One rational solution B. Two rational solution C. Two irrational solution D. One complex solution E. Two complex soltuions
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find the determinant \[\sqrt{b^2 - 4ac}\]. where a = 3, b = -7 and c = -4
Did you find the discriminant, b^2-4ac? It will tell you exactly what kind of solutions you have. D=0 means 1 rational solution D>0 and a perfect square means 2 rational solutions D>0 and not a perfect square means 2 irrational solutions D<0 means 2 complex solutions A quadratic equation can't have 1 complex solution.
sorry discriminant
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