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OpenStudy (anonymous):
Hey, can anyone help me with algebra 2 logs?
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OpenStudy (anonymous):
Sure
OpenStudy (anonymous):
i need help right now with finding inverse functions of logs
OpenStudy (anonymous):
can you post the problem?
OpenStudy (anonymous):
\[y=1/2(3)^x+1-5\] and I need help finding the inverse
OpenStudy (anonymous):
also +1 is apart of the exponent, it should be up high hahaha
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OpenStudy (anonymous):
so it should be (x+1) for the exponent?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
is log in the problem?
OpenStudy (anonymous):
no, it's just on my review guide of a ton of other log stuff hahha. If you don't understand this problem, could you try helping me with another?
OpenStudy (anonymous):
I could try
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