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Mathematics 7 Online
OpenStudy (anonymous):

Stuck with some circle work. Ill post the picture.

OpenStudy (anonymous):

Heres what im stuck on.

OpenStudy (solomonzelman):

attachment isn't working for me, can't help. Sorry-:( OTHER PEOPLE CAN THOUGH

OpenStudy (anonymous):

Wah):

OpenStudy (anonymous):

all 3 you want help with ?

OpenStudy (anonymous):

Well I couldn't find a way to post just the first one. But the first one I just need explaining with and then hopefully I will then understand how to do the rest

OpenStudy (anonymous):

first one, you have a Right angled triangle because that's a property of tangents, right?, any ideas on how to find x?

OpenStudy (anonymous):

Not a single clue.

OpenStudy (anonymous):

You are trying to find the value of x then you got to divide first then multiply

OpenStudy (anonymous):

do u know Pythagorean theorem? and can you apply it here?

OpenStudy (anonymous):

You use a little bit of Pythagorean thermo here .

OpenStudy (anonymous):

ok, yeah I know it. Yeah I can. \[24^{2}+32^{2}=c ^{2}\]

OpenStudy (anonymous):

Yes there you go ;)

OpenStudy (anonymous):

|dw:1401278518554:dw| in your formula c = 32 + x right? can you find x ? solve a quadratic equation

OpenStudy (anonymous):

\[x ^{2} + 64x - 24^{2} = 0\] do you get the same?

OpenStudy (anonymous):

Yes sir

OpenStudy (anonymous):

jermiah u r spamming here, shall i leave this Q to you and get out of here?

OpenStudy (anonymous):

No hes not spamming. but Im kind of confused. You lost me.

OpenStudy (anonymous):

No I am not spamming and no answer the question .

OpenStudy (anonymous):

Kx2bay did you get the answer yet?

OpenStudy (anonymous):

@kx2bay ?

OpenStudy (anonymous):

I guess I am going to answer this question myself then huh

OpenStudy (anonymous):

lol.i guess

OpenStudy (anonymous):

112? right

OpenStudy (anonymous):

Lol yes lol

OpenStudy (anonymous):

well duh! xD

OpenStudy (anonymous):

Now you got it;)

OpenStudy (anonymous):

hey brb okay

OpenStudy (anonymous):

Can I get your number so I can call you

OpenStudy (anonymous):

no

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