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F"(x) = 4x + sin(x) Find F(x) I came up with ( (2x^3)/(3) ) - sin(x) + C + D Can someone tell me if this is correct? I'll give a medal! :)
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first integration gives 4x^2/2 - cos x + c = 2x^2 - cos x + c second integration; 2x^3 / 3 - sin x + C there's no need to write 2 constants of integration
Hm, turns out it should have Cx + D. So it's wrong :(
2x^3 / 3 +sin x +c
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