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log3 27 – x = 5
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Assume this is log 3 (27-x) = 5.
ok
Convert to an exponent.
log 27-x^3=5
|dw:1401314927726:dw|
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log3(27-x)=5?
You are making the log into an exponent. So it will be \[3^{5}=27-x\]
oh ok. So after I solve for x?
Yes Determine what 3^5 is then subtract 27 from both sides to get x.
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