Anyone help me out with this question..
Well you're given two sides and an angle |dw:1401316218781:dw| And to determine the side we can use trigonometry SOH-CAH-TOA SOH=sin(of angle)=opposite of angle/hypotenuse CAH=cos(of angle)=adjacent of angle/hypotenuse TOA=tan(of angle)=opposite of angle/adjacent of angle So in your case we want to find the angle opposite of the angle So we can use SOH sin(34)=x/10 First type in sin 34 into a cal. you get 0.5591929035 Now you have 0.5591929035 = x/10 solve for x by multiplying by 10 on both sides You get 5.591 Round to the nearest tenth and you get 5.6
6.5 6.0 7.0 3.0
Those are the answer choices but I believe it would be 6.0.
Well if you do TOA TOA=tan(of angle)=opposite of angle/adjacent of angle tan(34)=x/4 tan 34 = 0.6745085168 0.6745085168 = x/4 multiply by 4 on both sides to find x 2.698 or 2.7 It could be either B or D...
Hmm..
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