Question

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

k = a0

Answer 1

\[\large f(x) = 112 - kx\]
\[\large f(-3) = 121\]

If this is true...we should be able to plug in -3 for 'x' in the first equation...and solve for 'k'

\[\large f(x)= 112 - kx \rightarrow f(-3) = 112 + 3k\]

since we know f(-3) = 121...we can plug that into our equationnow

\[\large 121 = 112 + 3k\]

Can you solve that for 'k'?