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find the exact value of sin(4pi/3-7pi/4)
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\[\sin (4\Pi -7\Pi/4)=\sin(9\Pi/4)=\sin(\Pi/4) becouse 9\Pi/4 and \Pi/4 are coterminal angles \]
Therfore the answer is \[\sqrt{2/}2\]
\[\sin\left(\frac{4\pi}{3}-\frac{7\pi}{4}\right)=\sin\frac{7\pi}{4}\cos\frac{4\pi}{3}-\sin\frac{4\pi}{3}\cos\frac{7\pi}{4}\]
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