Question

Help

Answer 1

just the start... hard problems - yet to come :P
but please help me wid this problem for now

Answer 2

haha

Answer 3

Selecting \(r\) things from total of \(n\) thing has
\(\Large ^nC_r\)
number of ways

Answer 4

selecting 1 cherry from 6 cherries will be ?

Answer 5

yeah and few of them are same things

Answer 6

6 ways

Answer 7

selecting 2 lemon candies from 2 lemon candies ?

Answer 8

1 way

Answer 9

correct!
so thats your numerator

Answer 10

selecting 3 things from total of 6+2+3 things ?

Answer 11

wow that looks simpler than i had thought xD

Answer 12

would the denominator be 11 C 3 ?

Answer 13

correct :)

Answer 14

thanks so much :)

Answer 15

welcome ^_^
Its easy because you have taken an easy problem, Permutation, Combinations can be really tricky sometimes :)