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Alright they give me a right triangle and they give me a interior angle of 58 and a outside of 4.0 I need help on how to solve this
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can you draw it, with the draw button
|dw:1401462291579:dw|
what is 4.0? a side-length?
|dw:1401462481934:dw|
thats how it looks
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and they want me to solve for x
yes it is a side length
how would i solve this ?
do you remember that \[\tan\theta=\frac{\text{opposite side}}{\text{adjacent side}}\]?
i dont really remember it how would i plug that in with my question ?
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well you have theta is 58°, and you have the opposite side is 4.0
\[{\text{adjacent side}}=\frac{\text{opposite side}}{\tan\theta}\]
x = 4.0 / tan(58°)
i got 14.5 i dont know if thats right
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