Question

what is the sin of A
A.8/15
B.8/17
C.17/15
D.15/17

Answer 1

Because \(\Large AC^2=17^2=289\) and \(\Large AB^2 + BC^2=8^2+15^2=289\)
So, \(\Large \triangle ABC \) is a right triangle.
\(\Large \Rightarrow sinA=\frac{BC}{AC}=\frac{15}{17}\)

Answer 2

thank you will you help me some more