Question

Help me convert to rectangular coordinates (-7,(2 pi)/3)

Answer 1

@jdoe0001 could you help me out?

Answer 2

\(\large \begin{array}{llll}
\left(-7,\frac{2\pi}{3}\right)\\
\quad \uparrow \quad \uparrow \\
\quad r\quad \theta
\end{array} recall\implies
\begin{array}{llll}
x=rsin(\theta)\\
y=rcos(\theta)
\end{array}\)

Answer 3

ehh rather \(\large \begin{array}{llll}
\left(-7,\frac{2\pi}{3}\right)\\
\quad \uparrow \quad \uparrow \\
\quad r\quad \theta
\end{array} recall\implies
\begin{array}{llll}
x=rcos(\theta)\\
y=rsin(\theta)
\end{array}
\\ \quad \\
\implies (x,y)\implies [rcos(\theta),rsin(\theta)]\)

Answer 4

so check your Unit Circle for the values of that angle :)