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Write the equation of a circle with center P(0, -3) and radius 8. a.) x2 + (y + 3)2 = 64 b.) x2 + (y - 3)2 = 64 c.) (x - 3)2 + (y + 3)2 = 64 d.) (x - 3)2 + y2 = 64
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Hint: \[\Large (x-h)^2 + (y-k)^2 = r^2\] is the general equation of a circle. The center is (h,k) and the radius is r.
thank you i got b
you are close
but b is incorrect
ohh um ill try again hang on
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notice in choice b how there is a "y-3" compare y-3 with y-k this tells us that k = 3 and the y coordinate of the center is 3
is it a?
but we want the y coordinate of the center to be -3
it is because y+3 is the same as y - (-3)
i just realised that its two negatives that make a posotive
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that's one way you can think of it
thank you
you're welcome
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