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Mathematics 17 Online
OpenStudy (anonymous):

please help

OpenStudy (anonymous):

81+z=103, z=?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

Notice that this question is just trying to mess with you, it says that you want to find a z-value that allows X to = both positive and negative 9, and still solve the equation, well lucky for you, no matter if X=9 or X=-9, since\[x^2=(9)^2=(-9)^2=81\]so using that logic, you get what kx2bay showed you

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