Question

find the zeros of -2x(x-5)(x^2-36)

Answer 1

(5,0) and (6,0)

Answer 2

well thats not quite right

there are 4 zeros,

and can be found by letting the linear factors equal zero and then solving for x.

so you'll have

-2x = 0

x - 5 = 0

x^2 - 36 = 0

solve each equation for x and you'll have the 4 zeros.

Answer 3

oops and quadratic factor equal zero