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OpenStudy (anonymous):
How would I find the limit of: lim x->3 (x-3)/(x^2-9)
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OpenStudy (ranga):
Factor the denominator and cancel any common factor with the numerator and then take the limit.
OpenStudy (anonymous):
(x^2-a^2) = (x+a)(x-a)
OpenStudy (anonymous):
ok i got 1/x+3 so do i substitute the x in the denominator and get 1/6 ?
OpenStudy (anonymous):
ye
OpenStudy (anonymous):
ok thank you
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