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The sum of three consecutive even integers is 120. Find the numbers.
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Let \(x\) be the first even integer. The next two would then be \(x+2\) and \(x+4\). Their sum is 120, or \[x+(x+2)+(x+4)=3x+6=120\] Solve for \(x\), then find \(x+2\) and \(x+4\).
Ah yes even numbers, you're correct @SithsAndGiggles
thank you
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