Question

Maybe I'm over-thinking this integral, but I don't know how to start it

Answer 1

\[\LARGE \int_{0}^{\pi/2}~cos^2\theta~d \theta\]

Answer 2

use \(\cos (2\theta) = 2\cos^2\theta - 1\)

Answer 3

\(\large \implies \cos^2\theta = \dfrac{1+\cos(2\theta)}{2}\)

Answer 4

I forgot about that formula, thanks gane :)

Answer 5

np :)