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1+3+5+7+...+999
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\(\LARGE\color{purple}{ \bf d=2 }\) \(\LARGE\color{purple}{ \bf a_n=a_1+d(n-1) }\) , in your case, \(\LARGE\color{purple}{ \bf a_n=1+2(n-1) }\) for any n. What exactly do you need to find ?
Sum of all terms?
To find the sum using Gauss's approach
1+999=1000 3+997=1000 5+995=1000 . . Just find out how many such pairs are there
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