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Topic: Base e and Natural Logarithms Directions: Solve each equation or inequality round to nearest ten thousandth Problem: 1-2e^2x=-19
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\[-2 e ^{2x}=-19-1=-20,e ^{2x}=10,\ln e ^{2x}=\ln 10,2 x=\frac{ {\ln 10} }{ \ln e }=\ln 10\] x=?
@surjithayer I am confused can you clear that confusion up please
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