Question

The 5th term of an arithmetic sequence described by the rule tn=19-3n, is ?
a) -3
b)-11
c) 11
d) 5
e) 7
I would think it would be 4 t5=19−3∗5=4 but that is apparently not an answer so which one is?

Answer 1

Begin the n value with 0, meaning that the n for the 5th term would actually be 4, so 19-3(4)=7