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Find x, which is the same as length BA http://i.imgur.com/hIebtn4.png @jim_thompson5910
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Solve for x \[\Large \frac{CA}{CB} = \frac{DF}{DE}\] \[\Large \frac{8+x}{8} = \frac{10+25}{10}\]
what is the next step after that?
@jim_thompson5910 is there another step?
yes there are many steps after that you need to fully isolate x (get it by itself)
\[\Large \frac{CA}{CB} = \frac{DF}{DE}\] \[\Large \frac{8+x}{8} = \frac{10+25}{10}\] \[\Large \frac{8+x}{8} = \frac{35}{10}\] \[\Large 10(8+x) = 8*35\] \[\Large 80 + 10x = 280\] I'll let you finish up
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can you show me how?
give it a shot and tell me what you get
okay thank you
have you solved linear equations before?
x=20
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that is correct
Thank you :)
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