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A 30°-60°-90° triangle has a hypotenuse with a length of 10. What is the length of the longer leg of the triangle?
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10/2 = 5 shortest leg of a 306090 triangle is always half the hypotenuse also cos(30)=x/10 so 10cos(30) = x cos (30) = 1/2 so 10 *1/2 = 5 sin(30) = square root of 3 (read: root 3 or 3 ^.5) over two so if you want the other leg (the longer short one) then you do 10(3^.5)/2 or 5(3^.5) are you in CAVA?
Thank you! And no, i'm not in CAVA.
You're Welcome :) Oh, I had the same question a while ago and thanks for the medal :D
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