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Mathematics 10 Online
OpenStudy (anonymous):

How would I factor (x+1)^3 (4x-9)-(16x+9)(x+1)^2 ?

OpenStudy (anonymous):

\[(x+1)^3 (4x-9)-(16x+9)(x+1)^2 \]

OpenStudy (anonymous):

\[(x+1)^{2}((4x-9)(x+1)-(16+9))\]

OpenStudy (anonymous):

according to a factor calculator the anwer will be \[(x+1)^2 (4x+3)(x-6)\]

OpenStudy (anonymous):

haha, ok. Then you got it.

OpenStudy (anonymous):

well i need to figure out how to find that though.

OpenStudy (anonymous):

Found it online:\[(x+1)^2[(x+1)(4x-9)-(16x+9)] \]\[(x+1)^2[4x^2-9x+4x-9-16x-9]\]\[(x+1)^2[4x^2-21x-18] \]\[(x+1)^2[4x^2-24x+3x-18]\]\[(x+1)^2 (x-6) (4x+3)\]

OpenStudy (anonymous):

I just got confused cuz you left out the x with the 16.

OpenStudy (anonymous):

Ohh, yes it has the "x": sorry Y forgot

OpenStudy (anonymous):

Use this steps: 1,2,4,3,5 Those are the orders in the one you wrote 3 posts before

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