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How would I factor (x+1)^3 (4x-9)-(16x+9)(x+1)^2 ?
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\[(x+1)^3 (4x-9)-(16x+9)(x+1)^2 \]
\[(x+1)^{2}((4x-9)(x+1)-(16+9))\]
according to a factor calculator the anwer will be \[(x+1)^2 (4x+3)(x-6)\]
haha, ok. Then you got it.
well i need to figure out how to find that though.
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Found it online:\[(x+1)^2[(x+1)(4x-9)-(16x+9)] \]\[(x+1)^2[4x^2-9x+4x-9-16x-9]\]\[(x+1)^2[4x^2-21x-18] \]\[(x+1)^2[4x^2-24x+3x-18]\]\[(x+1)^2 (x-6) (4x+3)\]
I just got confused cuz you left out the x with the 16.
Ohh, yes it has the "x": sorry Y forgot
Use this steps: 1,2,4,3,5 Those are the orders in the one you wrote 3 posts before
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