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Mathematics 25 Online
OpenStudy (anonymous):

Find the magnitude and smallest possible angle of the vector a=<-2,2>

OpenStudy (anonymous):

|dw:1401769271495:dw|

OpenStudy (anonymous):

angle should be obvious from the picture magnitude, via pythagoras, is \(\sqrt{2^2+2^2}\)

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

but how do you get the smallest possible angle

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