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There are 8 runners in a race. How many ways can the runners finish first, second, and third? A.8 B.24 C.336 D.6720
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you know permutations? 8*7*6=?
Imagine you are GOD and first you will select one runner out of 8 for the first position then out of remaining 7 you will select the second and third from the remaining 6 So Ans = 8*7*6 = 336
it can be solve without imagin she/he a God -.-
Lol! Thank you both. @aviz great way of putting it!
c
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