Question

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was –3° C. What was the temperature of City A and City B on that day?

City A was 5° C, and City B was 4° C.

City A was 3° C, and City B was –1° C.

City A was 8° C, and City B was –3° C.

City A was 5° C, and City B was –5° C.

Answer 1

Answer is: "City A was 5° C, and City B was 4° C."

Solution:
4A=3B+8
A-2B=-3

4A-3B=8
4A-8B=-12
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5B=20
B=4 degree C

A=5 degree C

Answer 2

Thanks :)