Question

Studying for exam:

Answer 1

\[(\sqrt{12}+\sqrt{-27}) - (\sqrt{3}-\sqrt{-48})\]

Answer 2

Evaluate... I forgot how todo this.. it was in the start of the year

Answer 3

\[\sqrt{12} = \sqrt{4 * 3} = 2 \sqrt{3}\]

\[\sqrt{-27} = i \sqrt{27} = \sqrt{9*3} = 3\sqrt{3}\]


\[\sqrt{-48} = i \sqrt{48} =i \sqrt{3* 16} = 4i sqrt{3}\]

Answer 4

@boblovesmath I dont understand can you explain?