4. An 800.0 kg roller coaster car is at rest at the top of a 95 m hill. It rolls down the first drop to a height of 31 m. When it travels to the top of the second hill, it is moving at 28 m/s. It then rolls down the second hill until it is at ground level. Draw a picture of the roller coaster drop and calculate the kinetic and potential energy at the top and bottom of each hill.
can somebody help me please?
mgh=.5mv^2+mgh, the left side of the equation is at rest the right side is taking into account kinetic and potential energy
how would i calculate the kinetic and potential energy on both the top and the bottom? is it going to be different? sorry i am at a loss with this one
and if to calculate kinetic energy you need velocity and velocity is distance divided by time but the time is not given, then what do i do?
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