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Algebra 8 Online
OpenStudy (anonymous):

Serena has 3 necklaces, 6 pairs of earrings, and 4 bracelets in her jewelry box. How many different combinations of a necklace, a pair of earrings, and a bracelet can she wear?

OpenStudy (kropot72):

For each of the 3 choices of necklace, there are 6 choices of pairs of earrings. So there are 3 * 6 combinations of necklaces and earrings and each of these combinations can be combined with each of the 4 bracelets. Therefore the number of different combinations of a necklace, a pair of earrings, and a bracelet is given by: \[3\times6\times4=you\ can\ calculate\]

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