Question

@BSwan What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

A. x^2 + y^2 − 4x + 2y + 1 = 0

B. x^2 + y^2 + 4x − 2y + 1 = 0

C. x^2 + y^2 + 4x − 2y + 9 = 0

D. x^2 − y^2 + 2x + y + 1 = 0

Answer 1

to generate circle equation u need a center (a,b) and radius r
so the equation
(x-a)^2 + (y - b)^2 = r^2

Answer 2

u have the center (-2,1)
and a point on the arc

Answer 3

find r using the destance formula :)