Question

Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created?

Answer 1

@phi

Answer 2

I would first plot (1,6) and the line y= -2

Answer 3

you should expect the equation of a parabola

its vertex will be half way between the directrix and the focus

Answer 4

I'm completely confused. I have no idea how to do this at all :/

Answer 5

It is hard to explain here. If you have time, see
http://www.khanacademy.org/math/algebra2/conics_precalc/parabolas_precalc/v/parabola-focus-and-directrix-1