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Geometry question (medals for best solution)
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\(\large 1 = x(4-x)\) \(\theta = \arctan (1/x)\)
|dw:1402031379761:dw|
ok you used mean proportional theorem x/ 1 = 1 / (4-x)
im not sure about theta = arctan (1/x)
yes the geometric mean thingy : altitude = geometric mean of segments of hypotenuse
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oh ok , so that is just tan (theta )= 1 / x
|dw:1402031610907:dw|
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