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Diverges or converges?
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\[\LARGE \int_{0}^{\infty}~sin^2 \alpha~d \alpha\] I'm assuming diverges but I'm not sure how to show it.
\[\large \int \limits_0^{\infty} \sin^2 \alpha d\alpha = \lim \limits_{t\to \infty }\int \limits_0^{t} \sin^2 \alpha d\alpha \]
evaluate the integral and take the limit
right
use this : \(\sin^2 x = \dfrac{1-\cos (2x)}{2}\)
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