Question

vector question, BP,PC,AB,AC,AP are all vectors
A, B, C are vertices of a triangle with a point P on the side of BC. Given that 3BP =4PC, find k if 3AB+ 4AC= kAP

Answer 1

might help to draw out the triangle ....

Answer 2

AC = AB + BP + PC
AP = AB + BP

3AB+ 4AB + 4BP + 4PC= kAB + kBP

3AB - kAB + 4AB = kBP - 4BP - 4PC

3AB - kAB + 4AB = kBP - 4BP - 3BP

7AB - kAB = kBP -7BP

(7-k)AB = (k-7)BP

those are just some ideas that come to mind ...